Miscellaneous news and sphere eversion

Before we begin, there are a few late items of news worth discussing:

  • There is a free edition of Wolfram Mathematica for the Raspberry Pi, an increasingly popular versatile low-cost computer. More details are available over at The Aperiodical.
  • The first round of the British Mathematical Olympiad has taken place. Marking is scheduled for the forthcoming weekend, and high scores will be published soon after. Until then, you can see the questions on Joseph Myers’ website.
  • The TMS Call My Bluff (mentioned during the previous cp4space post) was won by the freshers’ team. They were winning 4-2, and James Munro gave each team a set of tangled Borromean rings as a tie-breaker (quite literally!). The non-freshers won the tie-breaker, increasing their score to 4-3. Many thanks to all who participated; it was a pleasure to host the event (and not merely because I was entitled to an excess of mince pies and port!).
  • You may have noticed the recent Diwali-themed cp4space banner (thanks, by the way, to the CUHCS committee for organising an awesome celebration!). This will soon be replaced with a Saturnalia banner, then a Christmas one, and ultimately the New Year banner. Since cp4space is over a year old, these are very re-usable.

Anyway, you’re probably eagerly anticipating another cp4space article, so here goes:

Sphere eversion

Suppose we have a circle in the plane, and wish to transform it into its reflection by a homotopy (continuous deformation). Moreover, at every point in time, the curve must be an immersion of the circle: it is allowed to smoothly self-intersect, but cannot have any cusps or singularities. Can the transformation be done?

The answer is no: we can approximate such a differentiable map by a smooth one. Then, the total curvature must be preserved during the homotopy, whereas a clockwise circle and anticlockwise circle have opposite total curvatures.

However, for a sphere in three-dimensional space, this proof fails and, remarkably, it is actually possible to evert a sphere. There’s a video explaining the problem and briefly demonstrating the solution discovered by Bill Thurston, who proved that it is possible to perturb an arbitrary homotopy to remove any singularities.

Another solution is symmetric with respect to time, with the half-way model being the Morin surface. If we conjugate a rotation of the Morin surface by 90° with a homotopy transforming a sphere into a Morin surface, then we get the complete sphere eversion. This is more ad hoc than Thurston’s corrugations, and does not generalise easily to more complicated surfaces.

The aforementioned Morin, who is a retired topologist, was blind from the age of six; despite this, he was able to not only find an explicit solution to sphere eversion, but also discover the first parametrisation of Boy’s surface, an immersion of the real projective plane.


Since the real projective plane can be described as a sphere where antipodal points are identified, we can deduce that Boy’s surface has an Euler characteristic of 1. It is also non-orientable, a property it shares with the better-known Klein bottle (which has Euler characteristic 0). Interestingly, the name of the Klein bottle and its common realisation as a bottle with its neck re-entering through a hole and connecting to the base are the result of a German mistranslation.

A very impressive theorem states that any connected compact surface can be identified uniquely up to homeomorphism by the Euler characteristic, orientability and number of boundary components. Hence, they can be described as connected sums of projective planes (‘crosscaps’), tori (‘handles’) and closed discs (‘holes’).

This entry was posted in Uncategorized. Bookmark the permalink.

Leave a Reply

Fill in your details below or click an icon to log in:

WordPress.com Logo

You are commenting using your WordPress.com account. Log Out / Change )

Twitter picture

You are commenting using your Twitter account. Log Out / Change )

Facebook photo

You are commenting using your Facebook account. Log Out / Change )

Google+ photo

You are commenting using your Google+ account. Log Out / Change )

Connecting to %s